Question

At McMeck High School they decided to calculate the average GPA of all 950 students. The

average GPA was 2.38 with a standard deviation of 0.59, what is the margin of error? Round

your answer to three decimal places.

Answer 1

The margin of error is approximately 0.034.

Step-by-step explanation:

To calculate the margin of error, we need to use the formula:

Margin of Error = (Z-score) x (Standard Deviation) / sqrt(Sample Size)

Given that the average GPA is 2.38, the standard deviation is 0.59, and the sample size is 950, we can calculate the margin of error as follows:

Z-score = 1.96 (for a 95% confidence interval)

Margin of Error = (1.96) x (0.59) / sqrt(950) = 0.034

Therefore, the margin of error is approximately 0.034.

Answer 2

The margin of error = 0.037

Step-by-step explanation:

Step-by-step explanation:-

Given that the mean of the Population(μ) = 2.38

Given that the standard deviation of the Population(σ) = 0.59

Given sample size 'n' = 950

Level of significance = 0.05

The critical value( Z₀.₀₅) = 1 .96

The margin of error is determined by

`M.E = (Z_(\alpha ) S.D)/(√(n) )`

`M.E = (1.96 (0.59))/(√(950) )`

M.E = 0.037

Final answer:-

The margin of error = 0.037