Answer:
19 cars
13 buses
Explanation:
We have a system of equations as follows
X + y = 32 -----1
3x + 27y = 408 ----2
x = car
y = bus
From equation 1
x + y = 32
x = 32 - y ---- 3
We put equation 3 into equation 2
3(32-y) + 27y = 408
96y -3y + 27y = 408
96 + 24y = 408
24y = 408 - 96
24y = 312
Divide through by 24 to get the value of y
Y = 312/24
Y = 13
We put the value of y in equation 3
x = 32 - 13
x = 19
So 19 cars would be needed for the trip and also 13 buses would also be needed