For a normal distribution, find the percent of the area greater than z=-1.83 A) 3.36% B) 46.64% C) 53.56% D) 96.64 %

asked Aug 13, 2018 15.9k views

2 votes

For a normal distribution, find the percent of the area greater than z=-1.83

A) 3.36%
B) 46.64%
C) 53.56%
D) 96.64 %

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$\mathbb P(Z>-1.83)\approx0.9664=96.64\%$

Msbg answered Aug 18, 2018

by Msbg

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