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In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI) 2HI + Ca(OH)2 --> Cal + 2H2O
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In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI)

2HI + Ca(OH)2 --> Cal + 2H2O

User Ingram
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2HI + Ca(OH)2 --> Cal + 2H2O. According to stoichiometry, 2 moles of HI reacts with 1 mole of Ca(OH)2. Therefore, 1.2 moles of HI will react with = 1.2/2 = 0.6 moles of Ca(OH)2. Hope this helps.
User Vaughan Hilts
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