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Suppose you had 10 mol of NaCl and you dissolved it in exactly 3.00 kg of pure water (the solvent). What would be the molality of the solution in mol/kg?

Suppose you had 10 mol of NaCl and you dissolved it in exactly 3.00 kg of pure water (the solvent). What would be the molality of the solution in mol/kg?
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Suppose you had 10 mol of NaCl and you dissolved it in exactly 3.00 kg of pure water (the solvent). What would be the molality of the solution in mol/kg?

User David Steinhauer
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Molality = number of moles of solute/mass of solvent in kg = 10/3 = 3.34 mol/kg.
User Abhaya
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