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Four consecutive odd integers can be represented by n, n+2, n+4, and n+6. If the sum of the 4 consecutive odd integer is 46, what are the integers?
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Four consecutive odd integers can be represented by n, n+2, n+4, and n+6. If the sum of the 4 consecutive odd integer is 46, what are the integers?

User Easeout
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1 Answer

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46 = n + n + 2 + n + 4 + n + 6
46 = 4n + 12

34 = 4n

n = 8.5

Is it definitely 46?
User Uhkkgjhfjf Jgkjkhj
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