Question

Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.

y + 2 = –3(x – 4)
y − 5 = 3(x + 11)
y = -3x –
y = x – 2
3x + y = 7

Answer 1

the answers are:

a. y + 2 = –3(x – 4)

c. y = -3x –

e. 3x + y = 7

Answer 2

So here we first want to put each equation into slope-intercept form.

`y-1=(x+2)\\ y=x+3\\\\ y + 2 = -3(x - 4)\\ y=-3x+12-2\\ y=-3x+10\\\\ y - 5 = 3(x + 11)\\ y=3x+33+5\\ y=3x+38\\\\ y = -3x - \\ y=-3x\\\\ y = x - 2\\\\ 3x + y = 7\\ y=-3x+7`
Since when two slopes are perpendicular they equal -1 when multiplied to one another and in slope-intercept form where y = mx + b and m is slope,
Thus you can set up this equation:
1 * m = -1
m = -1
So the slope of the perpendicular line is -1. Now you just look through the equations and find which ones have a slope of -1.
The other lines with that line are: -- Actually none of them have that slope. So you don't click any of them.

Sorry if this took too long, it was a LOT to type out ,:D