Question

The line perpendicular to y=1/2x-2 that passes through the point (0,3)

Answer 1

⇒For perpendicular lines when their gradients are multiplied they have to give -1, in this case we are given a line with gradient
`(1)/(2)` meaning the gradient of the line perpendicular to it will be -2 since

`-2*(1)/(2) =-1` this means that the gradient of the new line will be -2

⇒Now we have a point and gradient.

⇒And we know that the general equation for a straight line is y=mx+c

`3=-2(0)+c\\3=c\\c=3`

The equation of the line perpendicular to the given one is

y=-2x+3

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