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Do heavier cars really use more gasoline? Suppose a car is chosen at random. Let x be the weight of the car (in hundreds of pounds), and let y be the miles per gallon (mpg)

User Justsalt
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1 Answer

11 votes

Answer:

Answer is explained in the explanation section below.

Step-by-step explanation:

Solution:

Note: This question is incomplete and lacks necessary data to solve. But I have found the similar question on the internet. So, I will be using the data from that question to solve this question for the sack of concept and understanding.

Data Given:

x = 27 , 44 , 32 , 47, 23 , 40, 34, 52

y = 30, 19, 24, 13 , 29, 19, 21, 14

It is given that,

∑x = 299

∑y = 167


x^(2) = 11887


y^(2) = 3773

We are asked to verify the above values manually in this question.

So,

1. ∑x = 299

Let's verify it:

∑x = 27 + 44 + 32 + 47 + 23 + 40 + 34 + 52

∑x = 299

Yes, it is equal to the given value. Hence, verified.

2. ∑y = 167

Let's verify it:

∑y = 30 + 19 + 24 + 13 + 29 + 19 + 21 + 14

∑y = 169

No, it is not equal to the given value.

3. ∑
x^(2) = 11887

Let's verify it:

For this to find, first we need to square all the value of x individually and then add them together to verify.


x^(2) =
27^(2) +
44^(2) +
32^(2) +
47^(2) +
23^(2) +
40^(2) +
34^(2) +
52^(2)


x^(2) = 11,887

Yes, it is equal to the given value. Hence, verified.

4. ∑
y^(2) = 3773

Let's verify it:

Again, for this we need to find the squares of all the y values and then add them together to verify it.


y^(2) =
30^(2) +
19^(2) +
24^(2) +
13^(2) +
29^(2) +
19^(2) +
21^(2) +
14^(2)


y^(2) = 3,845

No, it is not equal to the given value.

User TooCooL
by
4.9k points