Question

The electric potential in a circuit is given by

V(t) = 320e^(−3.1t)
where t is measured in seconds and V is measured in volts.
How long does it take for the potential to drop from 200 volts to 100 volts?

Answer 1

Hello there.

How long does it take for the potential to drop from 200 volts to 100 volts?
0.36 - 0.15 = 0.21 s

Answer 2

We are given with the equationL
V(t) = 320 e^(-3.1t)
At V = 200
200 = 320 e^(-3.1t)
t = 0.15 s

100 = 320 e^(-3.1t)
t = 0.36 s

It takes 0.36 - 0.15 = 0.21 s for the voltage to drop from 200 to 100 volts.