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Given directed line segment with endpoints A(-3, 1) and B(5, 13), what is the coordinate that partitions the line segment into a ratio of 1:3?

A(4, –1)

B(–1, 4)

C(–⅓, 5)

D(5, –⅓)

User ChenBr
by
7.7k points

1 Answer

7 votes

Answer:

B(–1, 4)

Explanation:

We want to find a point P(x,y).

Since it is on the directed line segment AB in the ratio 1:3, it means that:


P - A = (1)/(1+3)(B-A)

So


P - A = (1)/(4)(B-A)

We apply this to both the x-coordinate and y-coordinate of P.

x-coordinate:

x-coordinate of A: -3

x-coordinate of B: 5

x-coordinate of P: x

So


P - A = (1)/(4)(B-A)


x - (-3) = (1)/(4)(5 - (-3))


x + 3 = (1)/(4) * 8


x + 3 = 2


x = -1

y-coordinate:

y-coordinate of A: 1

y-coordinate of B: 13

y-coordinate of P: y

So


P - A = (1)/(4)(B-A)


y - 1 = (1)/(4)(13 - 1)


y - 1 = (1)/(4) * 12


y - 1 = 3


y = 4

So the correct answer is given by option B.

User UmutKa
by
8.2k points
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