Question

For both circuits: Determine the potential difference on and the current through each resistor. Show your work and then check your answer with PhET

Answer 1

Answer is explained in the explanation section below.

Step-by-step explanation:

Note: This question is incomplete and lacks the necessary diagram of the circuits to solve for this question. However, I have found similar question on the internet and dragged the diagrams out of it. I have attached the diagrams of the circuits for your ease. It has two circuits to be solved. Attachment 1 refers to first circuit and Attachment 2 refers to second circuit.

Solution:

We are asked to find the potential difference and current through each resistor.

So,

Calculations for Circuit 1: Please refer to Attachment 1

First we need to find the Resistance:

Req =
`(9 . 6)/(9+6) +3`

R = 6.6 Ohm

Now, we know that:

V = IR

So,

I = V/R

V = 12 V

I = 12 V/ 6.6 ohm

I = 1.82 Amperes.

Now,

The Potential Difference through 3 ohm resistor:

P.D =
`V_(3)` = 1.82 x 3

`V_(3)` = 5.45 V

Now,

The Potential Difference through 6 ohm and 9 ohm resistor:

`V_(6/9)` = 12V - 5.45V

`V_(6/9)` = 6.545V

Now,

The current through 6 ohm is:

`I_(6)` =
`(6.545)/(6)`

`I_(6)` = 1.09 A

Now,

The Current through 9 ohm is:

`I_(9)` =
`(6.545)/(9)`

`I_(9)` = 0.72 A

Similarly,

Calculations for Circuit 2: Please refer to attachment 2:

Req =
`((30+50).90)/(90+(30+50)) +20`

Req = 62.35 ohm

I = V/R

I = 12 V/ 62.35ohm

I = 0.192 Amperes.

Now,

The The Potential Difference through 20 ohm resistor:

`V_(20)` = 20 x 0.192

`V_(20)` = 3.849 V

Now,

The The Potential Difference through 90 ohm resistor:

`V_(90/(30+50))` = 12 - 3.849

`V_(90/(30+50))` = 8.150

Now,

The Current through 90 ohm is:

`I_(90)` = 8.1509/90

`I_(90)` = 0.0905 Amperes

Now,

The Current through 30 and 50 ohm is:

`I_(30/50)` = 0.192 - 0.0905

`I_(30/50)` = 0.101 A

Now,

The Potential Difference through 50 ohm resistor:

`V_(50)` = 50 x 0.101

`V_(50)` = 5.094 V

The Potential Difference through 30 ohm resistor:

`V_(30)` = 30 x 0.101

`V_(30)` = 3.0566 V