Question

8. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle, and the bottle flies forward at 25 m/s. How fast is the ball traveling after hitting the bottle?

Answer 1

Answer: The ball is travelling with a speed of 5.5 m/s after hitting the bottle.

Step-by-step explanation:

To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

`m_1u_1+m_2u_2=m_1v_1+m_2v_2`

where,

`m_1,u_1\text{ and }v_1` are the mass, initial velocity and final velocity of ball.

`m_2,u_2\text{ and }v_2` are the mass, initial velocity and final velocity of bottle.

We are given:

`m_1=0.4kg\\u_1=18m/s\\v_1=?m/s\\m_2=0.2kg\\u_2=0m/s\\v_2=25m/s`

Putting values in above equation, we get:

`(0.4* 18)+(0.2* 0)=(0.4* v_1)+(0.2* 25)\\\\v_1=5.5m/s`

Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.