Answer:
C) 4moles
Step-by-step explanation:
Let's consider the following balanced equation.
2 H₂S(g) + 3 O₂(g) → 2 SO₂(g) + 2 H₂O(g)
The molar ratio of O₂(g) to SO₂(g) is 3:2. The moles of SO₂(g) produced from the reaction of 6 moles of O₂(g) are:
6 mol O₂(g) × (2 mol SO₂(g)/ 3 mol O₂(g)) = 4 mol SO₂(g)
When 6 moles of O₂(g) react with more than enough H₂S(g), 4 moles of SO₂(g) are produced.