Question

The circle below is centered at the point (-1,2) and has a radius of length 3. What is its equation?

Answer 1

(x-h)²+(y-k)²=r²

when the center is (h,k) and the radius is r

given

(-1,2) and r=3

(x-(-1))²+(y-2)²=3²

(x+1)²+(y-2)²=3²

C is answer

Answer 2

Option C is correct.

Explanation:

We have been given the center of circle: (-1,2) and radius of length 3.

The general equation of circle is:

`(x-h)^2+(y-k)^2=r^2`

Here, h= -1, k=2 and r=3

h and k is the center of circle

On substituting the values in the formula we get:

`(x-(-1))^2+(y-2)^2=3^2`

`\Rightarrow (x+1)^2+(y-2)^2=9`

Therefore, Option C is correct.