Question

The circle below is centered at the point (3,1) and has a radius of length 2. What is its equation?

Answer 1

It is letter B.
Equation of a circle is in the form:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the center of the circle with radius r.

Answer 2

The correct option is B.

Explanation:

The standard form of the circle is

`(x-h)^2+(y-k)^2=r^2`

Where, (h,k) is the center of the circle and r is the radius of the circle.

It is given that the center of the circle is (3,1) and the radius of the circle is 2.

The equation of the circle is

`(x-3)^2+(y-1)^2=2^2`

This equation is represents by option B, therefore option B is correct.