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At a depth of 40 m, the water pressure is 500 kPa. A diver breathing air (78% N2, 21% O2) at this depth would have what partial pressure of oxygen in his lungs?

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We are given with the composition of the air inside a breathing apparatus which is
78% N2
21% O2

The total pressure at a given depth is 500 kPa
The partial pressure of oxygen is
500 kPa (0.21) = 105 kPa
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