Question

What is the percentage concentration by mass of a solution that contains 0.098 kg of H2SO4 in 500.0 g of H2O?

Answer 1

mass of solute in g :

1 kg ---------- 1000 g
0.098 kg ------ ??

0.098 x 1000 / 1 => 98.0 g

mass of solvent = 500.0 g

Therefore:

% ( w/w ) = 98.0 / 98.0 + 500.0

% (w/w ) = 98.0 / 598.0

0.163 x 100 => 16.3 %

Answer 2

Answer: The percentage concentration by mass of a solution that contains 0.098 kg of
`H_2SO_4` in 500.0 g of
`H_2O` is 16.4%

Step-by-step explanation:

To calculate the mass percentage ,we use the formula:

`\text{Mass percent}=\frac{\text{Mass of} H_2SO_4}{\text{Molar mass of} H_2SO_4+mass of water}* 100`

Mass of
`H_2SO_4` = 0.098 kg= 98 g

Mass of water = 500 g

Putting values in above equation, we get:

`\text{Mass percent}=(98g)/(98+500)* 100=16.4\%`

Hence, percentage concentration by mass of a solution that contains 0.098 kg of
`H_2SO_4` in 500.0 g of
`H_2O` is 16.4%