Answer:
m = 506 grams of fluorine
Step-by-step explanation:
Given:
M = 19·10⁻³ kg / mol - molar mass of fluorine
V = 543.2 mL = 543.2·10⁻³ m³
p = 123456 Pa
t = 29.8°C
_____________________
m - ?
Temperature in degrees Kelvin:
T = 273.15 + t = 273.15 + 29.8 = 302.95 K
Clapeyron-Mendeleev law:
p·V = (m/M)·R·T
Mass of fluorine:
m = p·V·M / (R·T)
m = 123456·543.2·10⁻³·19·10⁻³ / (8,31·302.95) ≈ 0.506 kg
or m = 506 g