Question

When a volume of H2 reacts with an equal volume of Cl2 (assume you have 1 L of each) at the same temperature and pressure, what volume of product having the formula HCl is formed?

Question 4 answers

Answer 1

The volume of H₂ times two

Step-by-step explanation:

The reaction that takes place is:

• H₂ + Cl₂ → 2HCl

Under the assumption that the gases behave ideally, then the moles of H₂ and Cl₂ are the same, because they have the same volume, temperature and pressure.

We can use the formula PV=nRT to solve this problem. For now let's say the temperature is 293 K, the volume is 1 L and the pressure is 1 atm. The values themselves are not important, just the fact that T and P remain constant is.

• Using PV=nRT we calculate the moles of H₂

1 atm * 1 L = xmol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

xmol= 0.0416 mol

• From the reaction we know that the moles of HCl produced are double the moles of H₂, so the moles of HCl are 0.0416 * 2 = 0.0832 mol.

Finally we calculate the volume of HCl using PV=nRT:

1 atm * xL = 0.0832 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

xL = 2 L

So the volume of HCl is the volume of H₂ times two.

Answer 2

For the answer to the question above,
first case:

H2+Cl2-----> 2 HCl
considering gasses are behaving ideally, equal volumes of gasses at equal T and P contains an equal number of moles. This means

1 mole h2 + 1 mole of cl2 gives 2 moles of HCl

or 1 vol of h2 + 1 vol of cl2 gives 2 volumes of HCl

I hope my answer helped you.