Hi there!
Recall Newton's Second Law:
![\Sigma F = ma](https://img.qammunity.org/2023/formulas/physics/college/gd80734mjsexoiyux7v7mwewgxb0m0l5nv.png)
∑F = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
The block will be experiencing two forces; a tension force in the direction of its acceleration (+) and a friction force (-).
![\Sigma F = T - F_K](https://img.qammunity.org/2023/formulas/physics/high-school/fpwiybbrj2p4c94lsi84fdc6raah6s3zub.png)
The equation for kinetic friction force is:
![F_K = \mu mg](https://img.qammunity.org/2023/formulas/physics/high-school/vrm7ycopr0r956i6w3rmcc7ipgag7s504x.png)
Using Newton's Second Law:
![ma = T - \mu mg](https://img.qammunity.org/2023/formulas/physics/high-school/njwz47eokti3nzwyxtwfj6jha6o4uox178.png)
Plug in the givens and solve for 'T':
![T = ma + \mu mg\\ \\ T = m(a + \mu g)\\ \\ T = 20(3 + 0.4(9.8)) = \boxed{138.4 N}](https://img.qammunity.org/2023/formulas/physics/high-school/2ezyuv8n5ehpqk5afsj2vnerudhdi8xgv4.png)