In order to solve the problem, we should know the heat capacity of silver. Which is equal to 0.240 J/g C
The formula: H = mCpT
Where h is the energy applied
M is the mass
Cp is the specific heat
T is the change in temperature
125 J = ( 29.3 g ) ( 0.240 J/g C)
T Solve for T
T = 17.78 degree C increase