Question

If an object falls and ends with a velocity of 58.8 m/s, how long was the

object falling?

Answer 1

the time taken for the object to fall is 6 s.

Step-by-step explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

`h = (v^2)/(2g) \\\\h = ((58.8)^2)/(2(9.8)) \\\\h = 176.4 \ m`

The time to fall through the height is calculated as;

`h =ut+ (1)/(2) gt^2\\\\h = 0 + (1)/(2) gt^2\\\\h = (1)/(2) gt^2\\\\t= \sqrt{(2h)/(g) } \\\\t = \sqrt{(2* 176.4)/(9.8) } \\\\t = 6 \ s`

Therefore, the time taken for the object to fall is 6 s.