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If an object is thrown downward at 4.73 m/s and it falls for 6.21 seconds before landing, how fast is it falling the instant before it lands?

User Manoranjan
by
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1 Answer

7 votes

Answer:

65.59 m /s

Step-by-step explanation:

Initial velocity u = 4.73 m/s

Final velocity v = ?

time t = 6.21 s

acceleration = g = 9.8 m /s

v = u + gt

= 4.73 + 9.8 x 6.21

= 65.59 m /s .

User TorosFanny
by
6.7k points