Question

The sum of three consecutive even integers is 108. What is the largest number?

Answer 1

Smallest #: x
Medium #: x + 2
Largest #: x + 4

Equation:
(x) + (x+2) + (x+4)= 108
3x + 6 = 108
3x = 102
x = 34

Largest #: x + 4
Largest #: 34 + 4
Largest #: 38

Answer 2

The largest number is 38.

Explanation:

Given : The sum of three consecutive even integers is 108.

To find : What is the largest number?

Solution :

Consecutive even integers are integers having a difference of two between them.

Let the three consecutive numbers be
`2n , 2n + 2 , 2n + 4`

According to question,

The sum of three consecutive even integers is 108.

i.e.
`2n + 2n + 2 + 2n + 4 = 108`

`6n + 6 = 108`

Subtract 6 both side,

`6n = 102`

Divide by 6 both side,

`n=17`

So, The numbers are

`2n = 2* 17 = 34`

`2n + 2 = 34 + 2 = 36`

`2n + 4 = 34 + 4 = 38`

The sum of three consecutive even integers is 108 then integers are 34, 36, 38 .

The largest number among them is 38.