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If I know a5 = -48 and r = 2 in a geometric sequence, how do i find the 8th term and explicit formula? How can I calculate a1?

1 Answer

3 votes
Data:
a5 = - 48
Being r = q = 2
a1 = ?
a8 = ?
n (Number of terms)

Solving:

Formula (
geometric progression)


a_(n) = a_(1) *q^(n-1)

We have:
find the 1th (a1)


a_(n) = a_(1) *q^(n-1)

a_(5) = a_(1) *2^(5-1)

-48 = a_(1) *2^(4)

-48 = a_(1) *16

16a_(1) = -48

a_(1) = (-48)/(16)

\boxed{a_(1) =-3}

find the 8th (a8)


a_(n) = a_(1) *q^(n-1)

a_(8) = -3 *2^(8-1)

a_(8)= -3 *2^(7)

a_(8)= -3 *128

\boxed{a_(8) =-384}

Answer:

\boxed{a_(1) = -3}

\boxed{a_(8) = -384}
User Kamusett
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