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Differentiate.

y = ln(t)/t²

User Nodon
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1 Answer

6 votes
remember

the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/((g(x))^2)

deritivive of lnx is 1/x
derivitive of t^2=2t

so


((1/t)t^2-2tlnt)/((t^2)^2)=

(t-2tlnt)/(t^4)=

(1-2ln(t))/(t^3)
User AshesToAshes
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