Question

Over a period of 15 years, the attrition rate in a company has been observed to be an average 10% every year. Find the probability that exactly 5 employees chosen randomly from a team of 40 will quit in the year ahead.

Answer 1

blah blah blah blah blah blah blah blah the correct answer is 0.165

Answer 2

Answer: Probability that exactly 5 employees chosen randomly from a team of 40 will quit in the year ahead is 0.165.

Explanation:

Since we have given that

Total number of employees = 40

Number of employees are going to quit in the year ahead = 5

Rate of attrition = 10%

We will use "Binomial distribution":

Here, n = 40

x= 5

p = 0.1

q = 1-0.1=0.9

`P(X=x)=^nC_xp^xq^(n-x)`

`P(X=5)=^(40)C_5(0.1)^5(0.9)^(35)\\\\P(X=5)=0.165`

Hence, Probability that exactly 5 employees chosen randomly from a team of 40 will quit in the year ahead is 0.165.