Question

Which are the solutions of the quadratic equation?

x^2 = –5x – 3

Answer 1

add 5x+3 both sides
x^2+5x+3=0
must use quadratic equation
for
ax^2+bx+c=0
x=
`(-b+/- √(b^2-4ac) )/(2a)`

given
1x^2+5x+3
a=1
b=5
c=3

x=
`(-5+/- √(5^2-4(1)(3)) )/(2(1))`
x=
`(-5+/- √(25-12) )/(2)`
x=
`(-5+/- √(13) )/(2)`

x=
`(-5+ √(13) )/(2)` or
`(-5- √(13) )/(2)`