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5 votes
Find the values of a, b, and c.

a = 41, b = 144, 36
a = 77, b = 118, c = 62
a = 36, b = 103, c = 77
a = 36, b = 118, c = 62

Find the values of a, b, and c. a = 41, b = 144, 36 a = 77, b = 118, c = 62 a = 36, b-example-1
User Norbekoff
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2 Answers

5 votes
a = 36, b = 118, c = 62

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User MrTomahawk
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3 votes

Answer:

The correct option is 4.

Explanation:

If a transversal line intersect two parallel line, then the alternate interior angles are equal.


a^(\circ)=36^(\circ)

The value of a is 36.

The sum of two interior angle is equal to the exterior angle of third vertex.


77+c=139


c=139-77


c=62

The value of c is 62.

If two angles lie on a straight line, then they are supplementary angles and their sum is 180 degree.


b+c=180^(\circ)


b+62^(\circ)=180^(\circ)


b=180^(\circ)-62^(\circ)


b=118^(\circ)

The value of b is 118.

Therefore option 4 is correct.

User Rahul KP
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8.1k points