Question

a block of wood is floating in water. the weight of the part of the block above water is one-third of the total weight of the block. what is the weight of the water displaced by the block of wood? Explain your answer in terms of Archimedes` principle

Answer 1

The weight of the water displaced is the same as the total weight of the wood block. The fact that 1/3 of the block is above the water level does not matter if you just weigh the total block of wood , then the weight of the total block of wood = the weight of the water displaced by the block of wood. If you want to find density of the block of wood that is a different question - then you need the volume of the block of wood and the information about one- third of the total weight . I hope this helped

Answer 2

The weight of the water displaced by the block of wood is equal to the weight ''W'' of the block of wood.

Step-by-step explanation:

Let's start defining the Archimedes' principle.

The Archimedes' principle states that a body total or partially submerged in a fluid experiments a thrust force which direction and sense is vertically upward and which magnitude is equal to the weight of fluid evicted.

The sum of all vertical forces acting on the block of wood must be equal to zero.

I add a free-body diagram of the situation.