Question

Write an equation of the line with a y-intercept of -4 that is parallel to 6x-2y=13.

Answer 1

6x - 2y = 13
-2y = -6x + 13
y = 3x - 13/2....slope here is 3. A parallel line will have the same slope.

In y = mx + b form, the slope is in the m position and the y intercept is in the b position.

y = mx + b
slope(m) = 3
y int (b) = -4

so ur parallel equation is : y = 3x - 4

Answer 2

Since the line will be parallel to 6x - 2y = 13, then it will have the same slope.

6x - 2y = 13

-2y = -6x + 13

y = -6x/-2 + 13/-2

y = 3x - 6.5, comparing to y = mx + c, m = 3

So the slope, m = 3.

So since the new line has a y intercept of -4:

Using the format, y = mx + c, note c = y intercept = -4, slope, m = 3

y = mx + c

y = 3x + (-4)

y = 3x - 4

I hope this helped.