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A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that time, at which rate is the diver accelerating …

A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that time, at which rate is the diver accelerating …
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A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that time, at which rate is the diver accelerating ?

User StudentRik
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2 Answers

3 votes
Your answer would be 9.8
User Sabir
by
7.2k points
4 votes

Acceleration = (change in speed) / (time for the change)

= (49 m/s) / (5 seconds)

= (49 / 5) m/s / s

= 9.8 m/s²
User Brian Reischl
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7.2k points
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