Question

A line passes through (6,3) , (8,4) and (n,-2) what is the value of n.

Answer 1

`\left[\begin{array}{ccc}6&3&1\\8&4&1\\n&-2&1\end{array}\right]=0`

`6*4*1+3*n*1+8*(-2)*1-1*4*n-6*(-2)*1-8*3*1=0`

`24+3n-16-4n+12-24=0`

`3n-4n+\diagup\!\!\!\!\!24-16+12-\diagup\!\!\!\!\!24=0`

`3n-4n-16+12=0`

`-n-4=0`
Keep the number on the left incognito and Put the number on the right without incognito by changing the sign.

`-n =4` simplify by (-1)

`\boxed{n = - 4}`

Answer:

`\boxed{n = -4}`