Question

-16t^2+120=0. round to nearest hundredth

Answer 1

Solution:

1) Subtract 120 from both sides
-16{t}^{2}=-120

2) Divide both sides by -16
{t}^{2}=\frac{-120}{-16}

3) Two negatives make a positive
{t}^{2}=\frac{120}{16}

4) Simplify \frac{120}{16} to \frac{15}{2}
​
{t}^{2}=\frac{15}{2}

5) Take the square root of both sides
t=\pm \sqrt{\frac{15}{2}}

6) Simplify \sqrt{\frac{15}{2}} to \frac{\sqrt{15}}{\sqrt{2}}

t=\pm \frac{\sqrt{15}}{\sqrt{2}}

Decimal Form: ±2.738613

Done!