Question

How resolve this equation 2x^2-3x-y=-5 -x+y=5

Answer 1

`-x+y=5\Rightarrow y=x+5`

Substitute
`y` in the other equation:

`2x^(2)-3x-(x+5)=-5`

`\Rightarrow 2x^(2)-3x-x-5=-5`

`\Rightarrow 2x^(2)-4x-5=-5`

`\Rightarrow 2x^(2)-4x=0`

`\Rightarrow 2x(x-2)=0`

So either

`2x=0\Rightarrow x=0\Rightarrow y=0+5=5`
or

`x-2=0\Rightarrow x=2\Rightarrow y=2+5=7`