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The length of a rectangle is 5 yd longer than its width. If the perimeter of the rectangle is 38 yd , find its area.

The length of a rectangle is 5 yd longer than its width. If the perimeter of the rectangle is 38 yd , find its area.
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The length of a rectangle is 5 yd longer than its width. If the perimeter of the rectangle is 38 yd , find its area.

User Hasith
by
8.9k points

1 Answer

1 vote
L=5+W
P=2(L+W)
38=2(L+W)
divide by 2
19=L+W
sub 5+W for L
19=5+W+W
19=5+2W
minus 5 both sides
14=2W
divid both sides by 2
7=W

L=5+W
L=5+7
L=12

area=LW
are=12 times 7
area=84 yd²
User Keagan
by
8.0k points
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