Question

What is the geometric sequence of 1/32, 1/8, 1/2, 2, 8

Answer 1

the formula for the nth term of a sequence with first term a1 and common ratio r is
an=a1(r)^(n-1)
r=a(n+1)/an

to find the common ratio, divide a term by the previous term
8/2=4
2/(1/2)=4
(1/2)/(1/8)=4
(1/8)/(1/32)=4
common ratio is 4
first erm is 1/32

an=(1/32)(4)^(n-1)

Answer 2

the geometric sequence is multiplied by 4