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The mean of a normally distributed dataset is 12, and the standard deviation is 2. what percent of the data points lies between 8 and 16?

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\mathbb P(8<X<16)=\mathbb P\left(\frac{8-12}2<\frac{X-12}2<\frac{16-12}2\right)=\mathbb P(-2<Z<2)

The empirical rule states that approximately
95\% of a normal distribution lies within two standard deviations of the mean.
User Hasanavi
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