Question

A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?

Answer 1

25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
1200/25 is equal to 48 N

Answer 2

The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.

Step-by-step explanation:

Given that,

Force = 1500 N

Area
`A= 25 m^2`

We need to find the force to be applied on a 0.8 m2 piston to lift the crate

Using formula of pressure

The pressure is the force upon area.

`P =(F)/(A)`

Where, F = force

A = area

Pressure for first force,

`P =(F)/(A)`

`P =(1500)/(25)`...(I)

Pressure for second force,

`P =(F)/(0.8)`...(II)

Equate the equations (I) and (II)

`(1500)/(25)=(F)/(0.8)`

`F=(1500*0.8)/(25)`

`F=48\ N`

Hence, The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.