Question

Find the equation of the line that contains the given point and is perpendicular to the given line. Write the equation in slope-intercept form, if possible, (6,2);y=-3x-3

Answer 1

`y=(1)/(3)x`

Explanation:

We need to find a line perpendicular to the given line. Let's first find the slope. If the line is perpendicular, it's slope is the negative reciprocal of the given line:

`(1)/(3)x`

Now that we know the slope, we can plug in the given points to solve for the y-intercept.

`y=(1)/(3)x+b\\ 2=(1)/(3)*6+b\\ 2=2+b\\ b=0`

Therefore the equation of the line is:

`y=(1)/(3)x`