Question

If f(x) = x5 – 1, g(x) = 5x2, and h(x) = 2x, which expression is equivalent to [g o f o h](9)?

Answer 1

[5*(2x)^2]^5 - 1 thats the answer

Answer 2

`[g o f o h](9)=5(18^5-1)`

Explanation:

f(x) = x^5 – 1, g(x) = 5x^2, and h(x) = 2x

[g o f o h](9)=g(f(h(9))

LEts fnd h(9) first

h(x)= 2x

h(9)= 2(9) =18

Now plug in 18 for h(9)

[g o f o h](9)=g(f(h(9)) = g(f(18))

now we find f(18)

f(x) = x^5 – 1, f(18)= 18^5 -1

Now we plug in 18^5 -1 for f(18)

[g o f o h](9)=g(f(h(9)) = g(18^5 -1)

Plug it in g(x)

g(x)= 5x^2

`g(18^5 -1)= 5(18^5-1)`

`[g o f o h](9)=5(18^5-1)`