Question

Evaluate x/y + 3z^2 for x= 2/3, y= 6/7, and z=3

a. 250/9
b. 169/9
c. 9/250
d. 9/169

Answer 1

remember that (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

(2/3)/(6/7)+3(3)^2=
(2/3)(7/6)+3(9)=
(2*7)/(3*6)+27=
(14/18)+27=
(7/9)+27=
7/9+243/9=
250/9

answer is A

Answer 2

x/y + 3z^2 for x= 2/3, y= 6/7, and z=3

=2/3 / 6/7 + 3(3^2)

=2/3 * 7/6 + 3(9)

= 7/9 + 27

= 7/9 + 243/9

= 250/9

answer is a. 250/9