Question

A watermelon cannon fires a watermelon vertically up into the air at a velocity of +9.5m/s, starting from an initial position of 1.2m above the ground. When the watermelon reaches the peak of its flight, what is:

a) the velocity _____

b) the acceleration _____

c) the elapsed time ______

d) the height above the ground _______

Answer 1

in 1 second the watermelon would be 10.7m above the ground. 2 seconds, 21.4m, 3 seconds,32.1m so on, so forth.