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What are the real and complex solutions of the polynomial equation x^3-8=0

2 Answers

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x³ - 8 = 0

x³ = 0 + 8

x³ = 8

Take the cube root of both sides

∛x³ = ∛8

∛(x*x*x) = ∛(2*2*2)

x = 2

Hope this helps.
User Waleed Amjad
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this is a difference of two cubes equation. To solve it, use this formula:

(a^3-b^3) = (a-b)(a^2+2ab+b^2)

or

x^3-8 = (x-2)(x^2+4x+4)


User Igotit
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