Question

Line A: y=-1/2x+3

line B:y=2x+-4

what is the slop of line A                    ps: you might need to graph it

what is the slop of line B

what is the solution to this system of equations

Answer 1

A) For the equation
`y=- (1)/(2)x+3`, the slope is
`- (1)/(2)`.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if
`m=- (1)/(2)`, the slope is
`- (1)/(2)`.

B) Since this equation is in the same form, you just find what m is equal to.
Since
`m=2`, that's the slope.

For the solution, set
`y=- (1)/(2)x+3` equal to
`y=2x-4`, so it would be put together like this:

`y=[tex]- (1)/(2)x+3=2x-4\\ -(1)/(2)=2x-7\\ 1(1)/(2)x=-7\\ x=-4.66667`
So your answer is -4.667.