Question

When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. What is the normal force acting on the bag by the floor?

Answer 1

well your going to have to decide by 27 of 23 with the remainder you just add it to the answer and then put the answer in this from 0.00.

Answer 2

Nc = 117.4 N

Step-by-step explanation:

Given:-

- The applied force, F = 27 N

- The coefficient of kinetic friction, uk = 0.23

Find:-

What is the normal force acting on the bag by the floor?

Solution:-

- Develop a FBD of the bag and mark all the forces acting on the bag. With x direction is parallel to the surface and y coordinate normal to the surface.

- There are four forces acting on the bag.

1 ) The applied force by Emma (F) acting in the right ( positive x - direction ).

2) The weight (W) of the bag vertically downwards ( negative y - direction )

3) The normal contact force (Nc) opposite in direction to weight of bag.

4) The frictional force (Ff) acting in opposite direction to the Emma push.

- The Normal force exerted by the surface on the bag is related to the frictional force Ff as follows:

Ff = uk*Nc

- We will apply the Newton's second law of motion in the x direction as follows. Assuming that bag moves with constant speed or does not accelerate then we have:

F - Ff = m*a

Where, a = 0,

F - Ff = 0

Ff = F = 27 N.

- Now use the Normal Force and Frictional Force relationship as follows:

Nc = Ff / uk

Nc = 27 / 0.23

Nc = 117.4 N