Answer:between 2 and 3, not including. Interval notation: (2,3)
Explanation:
Factor: x^2 -5x + 6 —> (x-3)(x-2)<0
Change sign to = and solve: x = 2 , 3
these are the x intercepts, the equation is not reflected over the y axis so we know the rest of the arc of the parabola is between 2 and 3