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How many moles of aluminum are needed to react with 3.6 mol of FeO? 2Al(s) + 3FeO(s) ----> 3Fe(s) + Al^2O^3(s) A. 2.4 mol B. 2.1 mol C. 1.2 mol D. 0.8 mol
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How many moles of aluminum are needed to react with 3.6 mol of FeO? 2Al(s) + 3FeO(s) ----> 3Fe(s) + Al^2O^3(s)

A. 2.4 mol
B. 2.1 mol
C. 1.2 mol
D. 0.8 mol

User RVr
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1 Answer

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3.6 mol (2 Al/3 FeO)=2.4 mol
User Urmelinho
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