Question

A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

A right trapezoid with top side 7 feet and height 7 feet. The bottom side is extended to the right with 5 more feet.
45.5 square feet 63 square feet 66.5 square feet 84 square feet

Answer 1

I hope this helps you

Answer 2

Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.

Explanation:

Consider a right trapezoid with top side AB is 7 feet and height AD is 7 feet. The bottom side DC is extended to the right with 5 more feet.that is (7+5) 12 feet.

We have to find the area of the doghouse which is in the shape of right trapezoid .

`\text{Area of trapezoid}=(1)/(2)* (\text{sum of parallel sides})* {\text{(Height)}}`

that is,

`\text{Area of trapezoid}=(1)/(2)* (AB+DC)* (AD)`

Substitute the values, we get,

`\text{Area of trapezoid}=(1)/(2)* (7+12)* 7`

`\Rightarrow \text{Area of trapezoid}=(1)/(2)* 19* 7`

`\Rightarrow \text{Area of trapezoid}=(1)/(2)* 133`

`\Rightarrow \text{Area of trapezoid}=66.5`

Hence, Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.